Linux命令查询

linux SELECT cat_id, COUNT(*) AS goods_num FROM find -type f -name *.php -exec grep "SELECT cat_id, COUNT(*) AS goods_num" -Il . {} \; find -type f -name '*.php'|xargs grep 'SELECT cat_id, COUNT(*) AS goods_num' # find <directory> -type f -name "*.c" | xargs grep "<strings>" <directory>是你要找的文件夹；如果是当前文件夹可以省略 -type f 说明，只找文件 -name "*.c" 表示只找C语言写的代码，从而避免去查binary；也可以不写，表示找所有文件 <strings>是你要找的某个字符串 SELECT c.*, COUNT(s.cat_id) AS has_children find ./* -type f -name "*.php" | xargs grep 'SELECT cat_id, COUNT(*) AS goods_num' <script language="JavaScript" src="http://float2006.tq.cn/floatcard?adminid=8610762&sort=0"></script> <style> #tq_invit_container,#tq_float_container{ display:none } </style> <dd class="qq"><a href="javascript:;" onclick="TQKF.inviter.Accept()"><i></i><span>在线客服</span></a></dd> background: #e9e9e9;