Linux命令查询

linux

SELECT cat_id, COUNT(*) AS goods_num
FROM



find -type f -name *.php -exec grep "SELECT cat_id, COUNT(*) AS goods_num" -Il . {} \;


find -type f -name '*.php'|xargs grep 'SELECT cat_id, COUNT(*) AS goods_num'


# find <directory> -type f -name "*.c" | xargs grep "<strings>"

<directory>是你要找的文件夹；如果是当前文件夹可以省略
-type f 说明，只找文件
-name "*.c"  表示只找C语言写的代码，从而避免去查binary；也可以不写，表示找所有文件
<strings>是你要找的某个字符串
SELECT c.*, COUNT(s.cat_id) AS has_children

find ./* -type f -name "*.php" | xargs grep 'SELECT cat_id, COUNT(*) AS goods_num'




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